0.248u^2-54.55u+1200=0

Solution for 0.248u^2-54.55u+1200=0 equation:

0.248u^2-54.55u+1200=0

a = 0.248; b = -54.55; c = +1200;
Δ = b2-4ac
Δ = -54.552-4·0.248·1200
Δ = 1785.3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54.55)-\sqrt{1785.3025}}{2*0.248}=\frac{54.55-\sqrt{1785.3025}}{0.496}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54.55)+\sqrt{1785.3025}}{2*0.248}=\frac{54.55+\sqrt{1785.3025}}{0.496}
$